Files
qemu/tests/tcg/multiarch/sigreturn-sigmask.c
Ilya Leoshkevich ef7e76a2cd tests/tcg: Test that sigreturn() does not corrupt the signal mask
Add a small test to prevent regressions.

Signed-off-by: Ilya Leoshkevich <iii@linux.ibm.com>
Message-ID: <20241108145237.37377-2-iii@linux.ibm.com>
Signed-off-by: Richard Henderson <richard.henderson@linaro.org>
2024-11-16 08:42:24 -08:00

52 lines
1.1 KiB
C

/*
* Test that sigreturn() does not corrupt the signal mask.
* Block SIGUSR2 and handle SIGUSR1.
* Then sigwait() SIGUSR2, which relies on it remaining blocked.
*
* SPDX-License-Identifier: GPL-2.0-or-later
*/
#include <assert.h>
#include <pthread.h>
#include <signal.h>
#include <stdlib.h>
#include <unistd.h>
int seen_sig = -1;
static void signal_func(int sig)
{
seen_sig = sig;
}
static void *thread_func(void *arg)
{
kill(getpid(), SIGUSR2);
return NULL;
}
int main(void)
{
struct sigaction act = {
.sa_handler = signal_func,
};
pthread_t thread;
sigset_t set;
int sig;
assert(sigaction(SIGUSR1, &act, NULL) == 0);
assert(sigemptyset(&set) == 0);
assert(sigaddset(&set, SIGUSR2) == 0);
assert(sigprocmask(SIG_BLOCK, &set, NULL) == 0);
kill(getpid(), SIGUSR1);
assert(seen_sig == SIGUSR1);
assert(pthread_create(&thread, NULL, thread_func, NULL) == 0);
assert(sigwait(&set, &sig) == 0);
assert(sig == SIGUSR2);
assert(pthread_join(thread, NULL) == 0);
return EXIT_SUCCESS;
}