Merge pull request #1888 from stevvooe/more-efficient-path-comparison

registry/storage: more efficient path compare in catalog
This commit is contained in:
Richard Scothern
2016-08-09 13:45:07 -07:00
committed by GitHub
2 changed files with 127 additions and 15 deletions

View File

@@ -38,7 +38,7 @@ func (reg *registry) Repositories(ctx context.Context, repos []string, last stri
_, file := path.Split(repoPath)
if file == "_layers" {
repoPath = strings.TrimSuffix(repoPath, "/_layers")
if pathGreaterThan(repoPath, last) {
if lessPath(last, repoPath) {
foundRepos = append(foundRepos, repoPath)
}
return ErrSkipDir
@@ -100,22 +100,53 @@ func (reg *registry) Enumerate(ctx context.Context, ingester func(string) error)
}
func pathGreaterThan(pathX, pathY string) (b bool) {
splitPathX := strings.SplitN(pathX, "/", 2)
splitPathY := strings.SplitN(pathY, "/", 2)
// lessPath returns true if one path a is less than path b.
//
// A component-wise comparison is done, rather than the lexical comparison of
// strings.
func lessPath(a, b string) bool {
// we provide this behavior by making separator always sort first.
return compareReplaceInline(a, b, '/', '\x00') < 0
}
if splitPathX[0] == splitPathY[0] {
if len(splitPathX) == 1 && len(splitPathY) == 1 {
return false
} else if len(splitPathX) == 1 && len(splitPathY) != 1 {
return false
} else if len(splitPathX) != 1 && len(splitPathY) == 1 {
return true
}
return pathGreaterThan(splitPathX[1], splitPathY[1])
// compareReplaceInline modifies runtime.cmpstring to replace old with new
// during a byte-wise comparison.
func compareReplaceInline(s1, s2 string, old, new byte) int {
// TODO(stevvooe): We are missing an optimization when the s1 and s2 have
// the exact same slice header. It will make the code unsafe but can
// provide some extra performance.
l := len(s1)
if len(s2) < l {
l = len(s2)
}
return splitPathX[0] > splitPathY[0]
for i := 0; i < l; i++ {
c1, c2 := s1[i], s2[i]
if c1 == old {
c1 = new
}
if c2 == old {
c2 = new
}
if c1 < c2 {
return -1
}
if c1 > c2 {
return +1
}
}
if len(s1) < len(s2) {
return -1
}
if len(s1) > len(s2) {
return +1
}
return 0
}