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tests: Continue closure-refcount test until all three threads are seen

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Previously, the test assumed that thread1 and thread2 would be scheduled
enough to set seen_thread{1,2} by the fact that the test runs for a high
number of iterations. On some platforms/schedulers, that’s not true,
which causes the test to spuriously fail.

Fix that by forcing the test to continue iterating until both threads
are seen. If this takes too long, the Meson test runner timeout will be
hit and the test will be terminated.

Signed-off-by: Philip Withnall <withnall@endlessm.com>
This commit is contained in:
Philip Withnall 2019-02-27 12:26:59 +00:00
parent 86f4a02b65
commit 1ae54da69b
1 changed files with 14 additions and 3 deletions
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17
gobject/tests/closure-refcount.c
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@ -258,7 +258,7 @@ test_closure_refcount (void)
TestClosureRefcountData test_data = { 0, };
GClosure *closure;
GTest *object;
guint i;
guint i, n_iterations;
object = g_object_new (G_TYPE_TEST, NULL);
closure = g_cclosure_new (G_CALLBACK (test_signal_handler), &test_data, destroy_data);
@ -281,10 +281,21 @@ test_closure_refcount (void)
* https://gitlab.gnome.org/GNOME/glib/issues/1316
* aka https://bugs.debian.org/880883 */
#if defined(__aarch64__) || defined(__arm__)
for (i = 0; i < 100000; i++)
n_iterations = 100000;
#else
for (i = 0; i < 1000000; i++)
n_iterations = 1000000;
#endif
/* Run the test for a reasonably high number of iterations, and ensure we
* don’t terminate until at least 10000 iterations have completed in both
* thread1 and thread2. Even though @n_iterations is high, we can’t guarantee
* that the scheduler allocates time fairly (or at all!) to thread1 or
* thread2. */
for (i = 0;
i < n_iterations ||
!g_atomic_int_get (&test_data.seen_thread1) ||
!g_atomic_int_get (&test_data.seen_thread2);
i++)
{
test_emissions (object);
if (i % 10000 == 0)