Fix initialization logic of GThreadPool if the first created pool is an exclusive one

Previously we would only ever run the initialization code once, but part
of it only if a non-exclusive pool was created. This caused the shared
state to be inconsistent if the first pool to be created was exclusive
and the second non-exclusive.

Fixes https://gitlab.gnome.org/GNOME/glib/issues/2012
This commit is contained in:
Sebastian Dröge 2020-01-25 11:08:22 +02:00
parent ac0c0b5b28
commit 78bae85d21

View File

@ -579,8 +579,8 @@ g_thread_pool_new (GFunc func,
G_LOCK (init);
if (!unused_thread_queue)
{
unused_thread_queue = g_async_queue_new ();
/* For the very first non-exclusive thread-pool we remember the thread
* scheduler settings of the thread creating the pool, if supported by
* the GThread implementation. This is then used for making sure that
@ -603,7 +603,7 @@ g_thread_pool_new (GFunc func,
* are created immediately below and are running forever, so they will
* automatically inherit the scheduler settings from this very thread.
*/
if (!exclusive)
if (!exclusive && !have_shared_thread_scheduler_settings && !spawn_thread_queue)
{
if (g_thread_get_scheduler_settings (&shared_thread_scheduler_settings))
{
@ -616,7 +616,6 @@ g_thread_pool_new (GFunc func,
g_thread_new ("pool-spawner", g_thread_pool_spawn_thread, NULL);
}
}
}
G_UNLOCK (init);
if (retval->pool.exclusive)