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gstrfuncs: Clarify that g_ascii_strtoull() accepts signed numbers
It’s perverse, but explicitly documented that strtoull() accepts numbers with a leading minus sign (`-`) and explicitly casts them to signed output. g_ascii_strtoull() is documented to do what strtoull() does (but locale independently), and its behaviour is correct. However, the documentation could be a lot clearer about this unexpected behaviour. Add a unit test for it too. Signed-off-by: Philip Withnall <withnall@endlessm.com>
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@ -1140,6 +1140,11 @@ g_parse_long_long (const gchar *nptr,
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* changing the current locale, since that would not be
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* thread-safe.
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*
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* Note that input with a leading minus sign (`-`) is accepted, and will return
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* the negation of the parsed number, unless that would overflow a #guint64.
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* Critically, this means you cannot assume that a short fixed length input will
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* never result in a low return value, as the input could have a leading `-`.
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*
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* This function is typically used when reading configuration
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* files or other non-user input that should be locale independent.
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* To handle input from the user you should normally use the
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@ -1098,6 +1098,7 @@ test_strtoll (void)
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check_uint64 ("18446744073709551616", "", 10, G_MAXUINT64, ERANGE);
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check_uint64 ("20xyz", "xyz", 10, 20, 0);
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check_uint64 ("-1", "", 10, G_MAXUINT64, 0);
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check_uint64 ("-FF4", "", 16, -((guint64) 0xFF4), 0);
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check_int64 ("0", "", 10, 0, 0);
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check_int64 ("9223372036854775807", "", 10, G_MAXINT64, 0);
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