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pass apiurl to source services (#234)

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Some source services need to know the apiurl, e.g. to lookup values
in the ~/.oscrc config file.

Closes #234.

https://github.com/openSUSE/osc/issues/234
This commit is contained in:
Adam Spiers 2016-10-01 22:50:33 +01:00
parent b4d4d3c027
commit 8c45eb64ad
1 changed files with 2 additions and 0 deletions
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2
osc/core.py
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@ -297,6 +297,7 @@ class Serviceinfo:
self.services.append(data) self.services.append(data)
def getProjectGlobalServices(self, apiurl, project, package): def getProjectGlobalServices(self, apiurl, project, package):
self.apiurl = apiurl
# get all project wide services in one file, we don't store it yet # get all project wide services in one file, we don't store it yet
u = makeurl(apiurl, ['source', project, package], query='cmd=getprojectservices') u = makeurl(apiurl, ['source', project, package], query='cmd=getprojectservices')
try: try:
@ -392,6 +393,7 @@ class Serviceinfo:
# set environment when using OBS 2.3 or later # set environment when using OBS 2.3 or later
if self.project != None: if self.project != None:
os.putenv("OBS_SERVICE_APIURL", self.apiurl)
os.putenv("OBS_SERVICE_PROJECT", self.project) os.putenv("OBS_SERVICE_PROJECT", self.project)
os.putenv("OBS_SERVICE_PACKAGE", self.package) os.putenv("OBS_SERVICE_PACKAGE", self.package)