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make help of osc init clearer
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@ -100,13 +100,19 @@ class Osc(cmdln.Cmdln):
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def do_init(self, subcmd, opts, project, package):
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def do_init(self, subcmd, opts, project, package):
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"""${cmd_name}: Initialize a directory as working copy
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"""${cmd_name}: Initialize a directory as working copy
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Initialize a directory to be a working copy of an
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Initialize an existing directory to be a working copy of an
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existing buildservice package.
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(already existing) buildservice package.
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(This is the same as checking out a
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package and then copying sources into the directory. It does NOT create
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a new package. To create a package, use 'osc meta', then 'osc init'.)
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(This is the same as checking out a package and then copying sources
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into the directory. It does NOT create a new package. To create a
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package, use 'osc meta pkg ... ...')
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You wouldn't normally use this command.
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To get a working copy of a package (e.g. for building it or working on
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it, you would normally use the checkout command. Use "osc help
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checkout" to get help for it.
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usage:
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usage:
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osc init PRJ PAC
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osc init PRJ PAC
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${cmd_option_list}
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${cmd_option_list}
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