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make help of osc init clearer

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Dr. Peter Poeml 2008-05-21 16:10:20 +00:00
parent d8245f5f36
commit ac55bcaa5a
1 changed files with 12 additions and 6 deletions
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16
osc/commandline.py
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@ -100,12 +100,18 @@ class Osc(cmdln.Cmdln):
def do_init(self, subcmd, opts, project, package):
"""${cmd_name}: Initialize a directory as working copy
Initialize a directory to be a working copy of an
existing buildservice package.
Initialize an existing directory to be a working copy of an
(already existing) buildservice package.
(This is the same as checking out a
package and then copying sources into the directory. It does NOT create
a new package. To create a package, use 'osc meta', then 'osc init'.)
(This is the same as checking out a package and then copying sources
into the directory. It does NOT create a new package. To create a
package, use 'osc meta pkg ... ...')
You wouldn't normally use this command.
To get a working copy of a package (e.g. for building it or working on
it, you would normally use the checkout command. Use "osc help
checkout" to get help for it.
usage:
osc init PRJ PAC