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ghash: Clarify that g_hash_table_add() always consumes the key

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Even if the key already exists in the table, `g_hash_table_add()` will
call the hash table’s key free func on the old key and will then replace
the old key with the newly-passed-in key. So `key` is always `(transfer
full)`.

In particular, `key` should never need to be freed by the caller if
`g_hash_table_add()` returns `FALSE`.

Signed-off-by: Philip Withnall <withnall@endlessm.com>
This commit is contained in:
Philip Withnall 2020-01-31 12:13:23 +00:00
parent b6b18f0190
commit b52bb75327
1 changed files with 5 additions and 1 deletions
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6
glib/ghash.c
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@ -1651,12 +1651,16 @@ g_hash_table_replace (GHashTable *hash_table,
/**
* g_hash_table_add:
* @hash_table: a #GHashTable
* @key: a key to insert
* @key: (transfer full): a key to insert
*
* This is a convenience function for using a #GHashTable as a set. It
* is equivalent to calling g_hash_table_replace() with @key as both the
* key and the value.
*
* In particular, this means that if @key already exists in the hash table, then
* the old copy of @key in the hash table is freed and @key replaces it in the
* table.
*
* When a hash table only ever contains keys that have themselves as the
* corresponding value it is able to be stored more efficiently. See
* the discussion in the section description.