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Fetch list of all projects lazily

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Currently osc <TAB><TAB> takes a long time to complete, which is incredibly
annoying. Only run "osc ls" if it is necessary for proper completion.
This commit is contained in:
Fabian Vogt 2020-03-13 15:32:03 +01:00
parent 3914b8c5e8
commit e11b49e2f1
1 changed files with 16 additions and 11 deletions
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27
dist/osc.complete vendored
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@ -132,18 +132,21 @@ if test -n "$alias" ; then
command="$command -A $alias"
fi
if test -s "${projects}" ; then
typeset -i ctime=$(command date -d "$(command stat -c '%z' ${projects})" +'%s')
typeset -i now=$(command date -d now +'%s')
if ((now - ctime > 86400)) ; then
if tmp=$(mktemp ${projects}.XXXXXX) ; then
command ${command} ls / >| $tmp
mv -uf $tmp ${projects}
fi
update_projects_list ()
{
if test -s "${projects}" ; then
typeset -i ctime=$(command date -d "$(command stat -c '%z' ${projects})" +'%s')
typeset -i now=$(command date -d now +'%s')
if ((now - ctime > 86400)) ; then
if tmp=$(mktemp ${projects}.XXXXXX) ; then
command ${command} ls / >| $tmp
mv -uf $tmp ${projects}
fi
fi
else
command ${command} ls / >| "${projects}"
fi
else
command ${command} ls / >| "${projects}"
fi
}
projects ()
{
@ -159,6 +162,7 @@ projects ()
argv[argc++]=$arg
done
shift $argc
update_projects_list
cur="$1"
if test -n "${cur}" ; then
list=($(command grep -E "^${cur}" ${projects}))
@ -273,6 +277,7 @@ targets ()
users ()
{
update_projects_list
if test -s ${projects} ; then
command sed -rn "/^home:$1/{ s/^home:([^:]*):.*/\1/p}" ${projects}|command sort -u
elif test -s ~/.oscrc; then